What is the derivative of f(x)=x^{-1} ?

The derivative of f(x)=x^{-1} is -1/(x^2)

What is the first derivative of f(x)=x^{-1} ?

The first derivative of f(x)=x^{-1} is -1/(x^2)

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derivative of

f (x) = x^{- 1}

- \frac{1}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 1 \cdot x^{- 1 - 1}

Simplify

- 1 \cdot x^{- 1 - 1} : - \frac{1}{x ^{2}}

= - \frac{1}{x ^{2}}

\int_{0}^{2 π} \frac{1 - cos ( x )}{2} d x

\int \frac{x ^{2} - 16}{x ^{4}} d x

n = 1 \sum \infty \frac{7}{n ( n + 1 )}

x \to 1 + lim (\frac{1}{x ^{1 - x}})

f (x) = 3 (x + 1)

What is the derivative of f(x)=x^{-1} ?
The derivative of f(x)=x^{-1} is -1/(x^2)
What is the first derivative of f(x)=x^{-1} ?
The first derivative of f(x)=x^{-1} is -1/(x^2)