What is the integral from 3 to 4 of (4+(24)/(x^2)) ?

The integral from 3 to 4 of (4+(24)/(x^2)) is 6

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integral from 3 to 4 of (4+(24)/(x^2))

\int_{3}^{4} (4 + \frac{24}{x ^{2}}) d x

6

Solution steps

\int_{3}^{4} 4 + \frac{24}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{3}^{4} 4 d x + \int_{3}^{4} \frac{24}{x ^{2}} d x

\int_{3}^{4} 4 d x = 4

\int_{3}^{4} \frac{24}{x ^{2}} d x = 2

= 4 + 2

Simplify

= 6

\frac{d y}{d x} + 7 x y = 0

x \to 2 lim (x^{3} - x^{2} - 4)

\frac{d}{d t} (3 t - t^{3})

\frac{d}{d x} (x^{2} x)

(3.2) (1.6)

What is the integral from 3 to 4 of (4+(24)/(x^2)) ?
The integral from 3 to 4 of (4+(24)/(x^2)) is 6