What is the solution for (dy)/(dx)+4y=e^{-x} ?

The solution for (dy)/(dx)+4y=e^{-x} is y= 1/(3e^x)+(c_{1})/(e^{4x)}

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(dy)/(dx)+4y=e^{-x}

\frac{d y}{d x} + 4 y = e^{- x}

y = \frac{1}{3 e ^{x}} + \frac{c _{1}}{e ^{4 x}}

Solution steps

\frac{d y}{d x} + 4 y = e^{- x}

Solve linear ODE:

y = \frac{1}{3 e ^{x}} + \frac{c _{1}}{e ^{4 x}}

y = \frac{1}{3 e ^{x}} + \frac{c _{1}}{e ^{4 x}}

n = 1 \sum \infty \frac{n}{e ^{2 n}}

\int \frac{1}{x} d (x) d x

y^{^{'}} = \frac{( x + y + 1 )}{( - x + 2 y + 3 )}

\frac{\partial}{\partial y} (50 y + 3250 - 100 x)

\int e^{v} d v

What is the solution for (dy)/(dx)+4y=e^{-x} ?
The solution for (dy)/(dx)+4y=e^{-x} is y= 1/(3e^x)+(c_{1})/(e^{4x)}