What is the solution for (dy)/(dx)=e^{5x+4y} ?

The solution for (dy)/(dx)=e^{5x+4y} is y=-(ln(-4/5 e^{5x}-c_{1}))/4

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(dy)/(dx)=e^{5x+4y}

\frac{d y}{d x} = e^{5 x + 4 y}

y = - \frac{ln ( - \frac{4}{5} e ^{5 x} - c _{1} )}{4}

Solution steps

\frac{d y}{d x} = e^{5 x + 4 y}

Solve separable ODE:

y = - \frac{ln ( - \frac{4}{5} e ^{5 x} - c _{1} )}{4}

y = - \frac{ln ( - \frac{4}{5} e ^{5 x} - c _{1} )}{4}

\int_{2}^{\infty} \frac{9}{2 x ^{2}} d x

\int 5 x cos (x) d x

\frac{( s + 2 )}{( s ^{2} + 3 s + 1 )}

\int \frac{5 x ^{3}}{( 5 - 3 x ^{4} ) ^{8}} d x

\frac{\partial}{\partial x} (sin (x^{2} + y^{2}))

What is the solution for (dy)/(dx)=e^{5x+4y} ?
The solution for (dy)/(dx)=e^{5x+4y} is y=-(ln(-4/5 e^{5x}-c_{1}))/4