(x^2+4xy)dx+xdy=0

Lösung

(x^{2} + 4 x y) d x + x d y = 0

y = - \frac{4 x - 1}{16} + \frac{c _{1}}{e ^{4 x}}

Schritte zur Lösung

(x^{2} + 4 x y) d x + x d y = 0

Solve linear ODE:

y = - \frac{4 x - 1}{16} + \frac{c _{1}}{e ^{4 x}}

y = - \frac{4 x - 1}{16} + \frac{c _{1}}{e ^{4 x}}

x \to 1 lim (\frac{5}{( x - 1 ) ^{2}})

\frac{d}{d x} ((1 + 2 x + 3 x^{2} + 4 x^{3})^{100})

in v erse l a pl a ce \frac{10}{( s - 2 ) ( s ^{3} + s )}

2 t y^{^{'}} = 4 y

\frac{d P}{d t} = 0.08 P (1 - \frac{P}{1000})