What is the derivative of 9e^{3x} ?

The derivative of 9e^{3x} is 27e^{3x}

What is the first derivative of 9e^{3x} ?

The first derivative of 9e^{3x} is 27e^{3x}

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derivative of

9 e^{3 x}

27 e^{3 x}

Solution steps

\frac{d}{d x} (9 e^{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{3 x})

Apply the chain rule:

e^{3 x} \frac{d}{d x} (3 x)

= e^{3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 9 e^{3 x} \cdot 3

Simplify

= 27 e^{3 x}

\int (x + 2)^{2} sin (x) d x

\frac{d}{d x} (x^{3} - x)

\int \frac{1}{5} - \frac{2}{x} d x

\frac{d y}{d x} = x x - 18

- 3 t sin (2 t)

What is the derivative of 9e^{3x} ?
The derivative of 9e^{3x} is 27e^{3x}
What is the first derivative of 9e^{3x} ?
The first derivative of 9e^{3x} is 27e^{3x}