What is the derivative of f(x)=ln(8-9x) ?

The derivative of f(x)=ln(8-9x) is -9/(8-9x)

What is the first derivative of f(x)=ln(8-9x) ?

The first derivative of f(x)=ln(8-9x) is -9/(8-9x)

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derivative of

f (x) = ln (8 - 9 x)

- \frac{9}{8 - 9 x}

Solution steps

\frac{d}{d x} (ln (8 - 9 x))

Apply the chain rule:

\frac{1}{8 - 9 x} \frac{d}{d x} (8 - 9 x)

= \frac{1}{8 - 9 x} \frac{d}{d x} (8 - 9 x)

\frac{d}{d x} (8 - 9 x) = - 9

= \frac{1}{8 - 9 x} (- 9)

Simplify

\frac{1}{8 - 9 x} (- 9) : - \frac{9}{8 - 9 x}

= - \frac{9}{8 - 9 x}

7 x^{2}, \frac{1}{7} x

\int \frac{3 x}{x ^{2} + 4} d x

\frac{\partial}{\partial x} (4 x y + x^{4} + y^{4})

\frac{d}{d x} (y - x)

x \to 1 lim (\frac{x ^{2}}{x ^{3} - x})

What is the derivative of f(x)=ln(8-9x) ?
The derivative of f(x)=ln(8-9x) is -9/(8-9x)
What is the first derivative of f(x)=ln(8-9x) ?
The first derivative of f(x)=ln(8-9x) is -9/(8-9x)