en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-y=0

Solution

y^{^{'}} - y = 0

Solution

y = e^{t + c_{1}}

Solution steps

y^{'} (t) - y = 0

Solve separable ODE:

y = e^{t + c_{1}}

y = e^{t + c_{1}}

Popular Examples

(\partial)/(\partial x)(3x^2y-y^3)

\frac{\partial}{\partial x} (3 x^{2} y - y^{3})

derivative of 2cos(t)derivative of

2 cos (t)

integral of sin^2(x)-sin^4(x)

\int sin^{2} (x) - sin^{4} (x) d x

derivative of (xsin^2(x)/(e^x-1))

\frac{d}{d x} (\frac{x sin ^{2} ( x )}{e ^{x} - 1})

limit as x approaches-1 of (x+1)/(x+1)

x \to - 1 lim (\frac{x + 1}{x + 1})

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=0 ?
The solution for y^'-y=0 is y=e^{t+c_{1}}