What is the derivative of y=70x^{-4} ?

The derivative of y=70x^{-4} is -(280)/(x^5)

What is the first derivative of y=70x^{-4} ?

The first derivative of y=70x^{-4} is -(280)/(x^5)

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derivative of

y = 70 x^{- 4}

- \frac{280}{x ^{5}}

Solution steps

\frac{d}{d x} (70 x^{- 4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 70 \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 70 (- 4 x^{- 4 - 1})

Simplify

70 (- 4 x^{- 4 - 1}) : - \frac{280}{x ^{5}}

= - \frac{280}{x ^{5}}

\int_{0}^{1} sin^{2} (x) d x

\frac{d}{d x} (x + h)

y = \frac{x}{x + 1}

x \to 0 lim (\frac{x ^{2}}{x - 2})

\frac{d}{d x} (sin (x) e^{x})

What is the derivative of y=70x^{-4} ?
The derivative of y=70x^{-4} is -(280)/(x^5)
What is the first derivative of y=70x^{-4} ?
The first derivative of y=70x^{-4} is -(280)/(x^5)