What is the derivative of x^2+6x+10 ?

The derivative of x^2+6x+10 is 2x+6

What is the first derivative of x^2+6x+10 ?

The first derivative of x^2+6x+10 is 2x+6

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\frac{d}{d x} (x^{2} + 6 x + 10)

2 x + 6

Solution steps

\frac{d}{d x} (x^{2} + 6 x + 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) + \frac{d}{d x} (10)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (10) = 0

= 2 x + 6 + 0

Simplify

= 2 x + 6

\int 6 x^{4} - 6 x^{3} + 5 x^{2} + C d x

\frac{50}{1 - 3 s ^{2}}

\frac{\partial}{\partial x} (s^{8} t + s t^{- 6})

5 x y^{5} + 8 x y = 39, (3, 1)

\int_{1}^{3} \frac{3}{x ^{2} + 4 x + 4} d x

What is the derivative of x^2+6x+10 ?
The derivative of x^2+6x+10 is 2x+6
What is the first derivative of x^2+6x+10 ?
The first derivative of x^2+6x+10 is 2x+6