What is the derivative of f(x)=3x^2cos(x)+8x ?

The derivative of f(x)=3x^2cos(x)+8x is 3(2xcos(x)-x^2sin(x))+8

What is the first derivative of f(x)=3x^2cos(x)+8x ?

The first derivative of f(x)=3x^2cos(x)+8x is 3(2xcos(x)-x^2sin(x))+8

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derivative of

f (x) = 3 x^{2} cos (x) + 8 x

3 (2 x cos (x) - x^{2} sin (x)) + 8

Solution steps

\frac{d}{d x} (3 x^{2} cos (x) + 8 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2} cos (x)) + \frac{d}{d x} (8 x)

\frac{d}{d x} (3 x^{2} cos (x)) = 3 (2 x cos (x) - x^{2} sin (x))

\frac{d}{d x} (8 x) = 8

= 3 (2 x cos (x) - x^{2} sin (x)) + 8

x \to 0 + lim ((sin (x))^{x})

\int cot^{3} (3 x) d x

x^{2} e^{- x}

\frac{d}{d x} (\frac{- 2}{9 x ^{\frac{5}{3}}})

\int_{6}^{7} \frac{x}{x ^{2} + 4 x + 13} d x

What is the derivative of f(x)=3x^2cos(x)+8x ?
The derivative of f(x)=3x^2cos(x)+8x is 3(2xcos(x)-x^2sin(x))+8
What is the first derivative of f(x)=3x^2cos(x)+8x ?
The first derivative of f(x)=3x^2cos(x)+8x is 3(2xcos(x)-x^2sin(x))+8