What is the derivative of 1-e^{2x} ?

The derivative of 1-e^{2x} is -2e^{2x}

What is the first derivative of 1-e^{2x} ?

The first derivative of 1-e^{2x} is -2e^{2x}

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\frac{d}{d x} (1 - e^{2 x})

- 2 e^{2 x}

Solution steps

\frac{d}{d x} (1 - e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (e^{2 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

= 0 - e^{2 x} \cdot 2

Simplify

= - 2 e^{2 x}

y^{^{''}} + 3 y^{^{'}} - 28 y = 0

y^{^{'}} = - y^{3}, y (0) = 1

\int \frac{1}{x ^{2}} + x d x

\frac{d}{d x} (x^{z (x)})

x \to 2 - lim (3 x + 6)

What is the derivative of 1-e^{2x} ?
The derivative of 1-e^{2x} is -2e^{2x}
What is the first derivative of 1-e^{2x} ?
The first derivative of 1-e^{2x} is -2e^{2x}