What is (\partial)/(\partial y)(x^2+xy-25) ?

The answer to (\partial)/(\partial y)(x^2+xy-25) is x

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(\partial)/(\partial y)(x^2+xy-25)

\frac{\partial}{\partial y} (x^{2} + x y - 25)

x

Solution steps

\frac{\partial}{\partial y} (x^{2} + x y - 25)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (x^{2}) + \frac{\partial}{\partial y} (x y) - \frac{\partial}{\partial y} (25)

\frac{\partial}{\partial y} (x^{2}) = 0

\frac{\partial}{\partial y} (x y) = x

\frac{\partial}{\partial y} (25) = 0

= 0 + x - 0

Simplify

= x

\int 2 y - 1 d y

y^{^{'}} + y = 2 t e^{- t} + t^{2}

\frac{d}{d x} ((2 x^{4} - 3 x)^{3})

\int \frac{3}{8} d x

\int \frac{2 x}{( x ^{2} - 1 )} d x

What is (\partial)/(\partial y)(x^2+xy-25) ?
The answer to (\partial)/(\partial y)(x^2+xy-25) is x