What is the d/(dy)(sqrt(y/2)) ?

The d/(dy)(sqrt(y/2)) is 1/(2sqrt(2)\sqrt{y)}

What is the first d/(dy)(sqrt(y/2)) ?

The first d/(dy)(sqrt(y/2)) is 1/(2sqrt(2)\sqrt{y)}

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\frac{d}{d y} (\frac{y}{2})

\frac{1}{2 2 y}

Solution steps

\frac{d}{d y} (\frac{y}{2})

Apply the chain rule:

\frac{1}{2 \frac{y}{2}} \frac{d}{d y} (\frac{y}{2})

= \frac{1}{2 \frac{y}{2}} \frac{d}{d y} (\frac{y}{2})

\frac{d}{d y} (\frac{y}{2}) = \frac{1}{2}

= \frac{1}{2 \frac{y}{2}} \cdot \frac{1}{2}

Simplify

\frac{1}{2 \frac{y}{2}} \cdot \frac{1}{2} : \frac{1}{2 2 y}

= \frac{1}{2 2 y}

\int_{0}^{2} x \cdot \frac{1}{2} (2 - x) d x

\frac{d}{d x} (6 x^{3} e^{- x})

f (x) = 3 x ln (x)

\frac{1}{3} x^{3} - 7 x + 5

n = 1 \sum \infty \frac{x ^{n}}{2 ^{n}}

What is the d/(dy)(sqrt(y/2)) ?
The d/(dy)(sqrt(y/2)) is 1/(2sqrt(2)\sqrt{y)}
What is the first d/(dy)(sqrt(y/2)) ?
The first d/(dy)(sqrt(y/2)) is 1/(2sqrt(2)\sqrt{y)}