What is the integral of xcos(5pi)x^2 ?

The integral of xcos(5pi)x^2 is -(x^4)/4+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of xcos(5pi)x^2

\int x cos (5 π) x^{2} d x

- \frac{x ^{4}}{4} + C

Solution steps

\int x cos (5 π) x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cos (5 π) \cdot \int x x^{2} d x

cos (5 π) = - 1

= (- 1) \cdot \int x x^{2} d x

Simplify

x x^{2} : x^{3}

= (- 1) \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= (- 1) \frac{x ^{4}}{4}

Simplify

= - \frac{x ^{4}}{4}

Add a constant to the solution

= - \frac{x ^{4}}{4} + C

\int \frac{9 x - 18}{x ^{3} - 2 x ^{2} - x + 2} d x

\frac{d y}{d x} = \frac{x y + 5 x - y - 5}{x y - 2 x + 6 y - 12}

\frac{d}{d x} ((x^{2} + 5 x + 1) f (x) (sin (3 x)))

\int x^{2} \cdot x - 2 d x

\int \frac{7 cos ^{5} ( x )}{sin ( x )} d x

What is the integral of xcos(5pi)x^2 ?
The integral of xcos(5pi)x^2 is -(x^4)/4+C