What is the derivative of e^{2x^2-1} ?

The derivative of e^{2x^2-1} is e^{2x^2-1}*4x

What is the first derivative of e^{2x^2-1} ?

The first derivative of e^{2x^2-1} is e^{2x^2-1}*4x

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\frac{d}{d x} (e^{2 x^{2} - 1})

e^{2 x^{2} - 1} \cdot 4 x

Solution steps

\frac{d}{d x} (e^{2 x^{2} - 1})

Apply the chain rule:

e^{2 x^{2} - 1} \frac{d}{d x} (2 x^{2} - 1)

= e^{2 x^{2} - 1} \frac{d}{d x} (2 x^{2} - 1)

\frac{d}{d x} (2 x^{2} - 1) = 4 x

= e^{2 x^{2} - 1} \cdot 4 x

\int_{0}^{8} \frac{1}{64 + x ^{2}} d x

\frac{d}{d x} (\frac{x sin ( 2 x )}{cos ( 3 x )})

8 t \frac{d y}{d t} + y = t^{5}

f (x) = x^{2} + 3 x

What is the derivative of e^{2x^2-1} ?
The derivative of e^{2x^2-1} is e^{2x^2-1}*4x
What is the first derivative of e^{2x^2-1} ?
The first derivative of e^{2x^2-1} is e^{2x^2-1}*4x