What is the tangent of f(x)=3x^2,(-1,3) ?

The tangent of f(x)=3x^2,(-1,3) is y=-6x-3

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tangent of f(x)=3x^2,(-1,3)

tangent of

f (x) = 3 x^{2}, (- 1, 3)

y = - 6 x - 3

Solution steps

Find the slope of

f (x) = 3 x^{2} : \frac{df ( x )}{d x} = 6 x

Compute the slope of

f (x) = 3 x^{2}

(- 1, 3) : m = - 6

Find the line with slope m=

- 6

and passing through

(- 1, 3) : y = - 6 x - 3

y = - 6 x - 3

g (t) = t

\frac{d}{d x} ((x^{2} + 2 x + 2)^{s i n (x)})

y^{^{'}} + y = x y^{4}

x \to \infty lim (3 + \frac{2}{x})

f (y) = y

What is the tangent of f(x)=3x^2,(-1,3) ?
The tangent of f(x)=3x^2,(-1,3) is y=-6x-3