What is the derivative of 3x^3-2x ?

The derivative of 3x^3-2x is 9x^2-2

What is the first derivative of 3x^3-2x ?

The first derivative of 3x^3-2x is 9x^2-2

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\frac{d}{d x} (3 x^{3} - 2 x)

9 x^{2} - 2

Solution steps

\frac{d}{d x} (3 x^{3} - 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{3}) - \frac{d}{d x} (2 x)

\frac{d}{d x} (3 x^{3}) = 9 x^{2}

\frac{d}{d x} (2 x) = 2

= 9 x^{2} - 2

\int sec^{4} (2 x) d x

x \to 4 - lim (e^{\frac{1}{x - 4}})

\int \frac{( 4 + x - 3 x )}{x} d x

\frac{d}{d x} (\frac{x ^{2}}{4} - \frac{ln ( x )}{2})

x \to - 9 lim (- 12)

What is the derivative of 3x^3-2x ?
The derivative of 3x^3-2x is 9x^2-2
What is the first derivative of 3x^3-2x ?
The first derivative of 3x^3-2x is 9x^2-2