What is the solution for (d^2y)/(dx^2)-2(dy)/(dx)+2y=0 ?

The solution for (d^2y)/(dx^2)-2(dy)/(dx)+2y=0 is y=e^x(c_{1}cos(x)+c_{2}sin(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(d^2y)/(dx^2)-2(dy)/(dx)+2y=0

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 2 y = 0

y = e^{x} (c_{1} cos (x) + c_{2} sin (x))

Solution steps

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + 2 y = 0

Solve linear ODE:

y = e^{x} (c_{1} cos (x) + c_{2} sin (x))

y = e^{x} (c_{1} cos (x) + c_{2} sin (x))

\int \frac{2 z}{1 - z ^{2}} d z

x \to 0 + lim (\frac{4}{x ^{2}})

\int 2 x y^{3} z^{4} d x

\int \frac{y - 2}{y + 3} d y

\frac{\partial}{\partial s} (s^{2} t^{2})

What is the solution for (d^2y)/(dx^2)-2(dy)/(dx)+2y=0 ?
The solution for (d^2y)/(dx^2)-2(dy)/(dx)+2y=0 is y=e^x(c_{1}cos(x)+c_{2}sin(x))