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Popular >

integral of (4-x)^2

Solution

\int (4 - x)^{2} d x

Solution

16 x - 4 x^{2} + \frac{x ^{3}}{3} + C

Solution steps

\int (4 - x)^{2} d x

Expand

(4 - x)^{2} : 16 - 8 x + x^{2}

= \int 16 - 8 x + x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 16 d x - \int 8 x d x + \int x^{2} d x

\int 16 d x = 16 x

\int 8 x d x = 4 x^{2}

\int x^{2} d x = \frac{x ^{3}}{3}

= 16 x - 4 x^{2} + \frac{x ^{3}}{3}

Add a constant to the solution

= 16 x - 4 x^{2} + \frac{x ^{3}}{3} + C

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Frequently Asked Questions (FAQ)

What is the integral of (4-x)^2 ?
The integral of (4-x)^2 is 16x-4x^2+(x^3)/3+C