What is the limit as x approaches infinity of sqrt(x^2-9),+x ?

The limit as x approaches infinity of sqrt(x^2-9),+x is ,sqrt(infinity)+infinity

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limit as x approaches infinity of sqrt(x^2-9),+x

x \to \infty lim (x^{2} - 9, + x)

, \infty + \infty

Solution steps

x \to \infty lim (x^{2} - 9, + x)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to \infty lim (x^{2} - 9,) + x \to \infty lim (x)

x \to \infty lim (x^{2} - 9,) =, \infty

x \to \infty lim (x) = \infty

=, \infty + \infty

x \to \infty lim (3 x^{3})

y^{^{''}} - 3 y^{^{'}} + 2 y = 2 e^{t}, y (0) = 0, y^{^{'}} (0) = 0

x \to 0 lim (\frac{1}{x} - 1)

\int e^{l n (x^{2})} d x

\int sec^{2} (5 x) tan^{6} (5 x) d x

What is the limit as x approaches infinity of sqrt(x^2-9),+x ?
The limit as x approaches infinity of sqrt(x^2-9),+x is ,sqrt(infinity)+infinity