What is the integral from 1 to 7 of w^2ln(w) ?

The integral from 1 to 7 of w^2ln(w) is -38+343/3 ln(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 7 of w^2ln(w)

\int_{1}^{7} w^{2} ln (w) d w

- 38 + \frac{343}{3} ln (7)

Decimal Notation

184.48239 \dots

Solution steps

\int_{1}^{7} w^{2} ln (w) d w

Apply Integration By Parts

: [\frac{1}{3} w^{3} ln (w) - \int \frac{w ^{2}}{3} d w]_{1}^{7}

= [\frac{1}{3} w^{3} ln (w) - \int \frac{w ^{2}}{3} d w]_{1}^{7}

\int \frac{w ^{2}}{3} d w = \frac{w ^{3}}{9}

= [\frac{1}{3} w^{3} ln (w) - \frac{w ^{3}}{9}]_{1}^{7}

Compute the boundaries:

- 38 + \frac{343}{3} ln (7)

= - 38 + \frac{343}{3} ln (7)

4 x^{2} + 3 x

\int_{9}^{18} 324 - x^{2} d x

\int cot (11 x) d x

\frac{d}{d x} (\frac{2}{1 + 4 x})

(16, - 2), (15, 86)

What is the integral from 1 to 7 of w^2ln(w) ?
The integral from 1 to 7 of w^2ln(w) is -38+343/3 ln(7)