What is the derivative of y=x+cos(x) ?

The derivative of y=x+cos(x) is 1-sin(x)

What is the first derivative of y=x+cos(x) ?

The first derivative of y=x+cos(x) is 1-sin(x)

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derivative of

y = x + cos (x)

1 - sin (x)

Solution steps

\frac{d}{d x} (x + cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (cos (x))

\frac{d x}{d x} = 1

\frac{d}{d x} (cos (x)) = - sin (x)

= 1 - sin (x)

\frac{d}{d x} (\frac{x}{1})

f (x) = \frac{12 x}{1 - x}

\frac{d y}{d x} = y (1 - y^{2})

\frac{\partial}{\partial x} (y sin (3 x))

What is the derivative of y=x+cos(x) ?
The derivative of y=x+cos(x) is 1-sin(x)
What is the first derivative of y=x+cos(x) ?
The first derivative of y=x+cos(x) is 1-sin(x)