What is the derivative of sin(pit) ?

The derivative of sin(pit) is cos(pit)pi

What is the first derivative of sin(pit) ?

The first derivative of sin(pit) is cos(pit)pi

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derivative of

sin (π t)

cos (π t) π

Solution steps

\frac{d}{d t} (sin (π t))

Apply the chain rule:

cos (π t) \frac{d}{d t} (π t)

= cos (π t) \frac{d}{d t} (π t)

\frac{d}{d t} (π t) = π

= cos (π t) π

y = 8 x, y = 8 x^{3}

\frac{d}{d x} (sin (y) + x y - x^{3})

\frac{d}{d x} ((x + 1)^{l n (x)})

y^{^{''}} + 2 y^{^{'}} = 2 x + 7 - e^{- 2 x}

\int_{- 1}^{1} (x^{2} - 1)^{2} d x

What is the derivative of sin(pit) ?
The derivative of sin(pit) is cos(pit)pi
What is the first derivative of sin(pit) ?
The first derivative of sin(pit) is cos(pit)pi