What is the derivative of f(x)=3x^2-ln(x) ?

The derivative of f(x)=3x^2-ln(x) is 6x-1/x

What is the first derivative of f(x)=3x^2-ln(x) ?

The first derivative of f(x)=3x^2-ln(x) is 6x-1/x

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derivative of

f (x) = 3 x^{2} - ln (x)

6 x - \frac{1}{x}

Solution steps

\frac{d}{d x} (3 x^{2} - ln (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (ln (x))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= 6 x - \frac{1}{x}

\frac{2}{x}, 3

x^{2} y^{^{''}} + x y^{^{'}} - y = \frac{1}{x}

\frac{d y}{d x} = (\frac{4 y + 3}{8 x + 5})^{2}

\int cos (x^{2}) x d x

\frac{8}{( s ^{2} + 6 s + 8 )}

What is the derivative of f(x)=3x^2-ln(x) ?
The derivative of f(x)=3x^2-ln(x) is 6x-1/x
What is the first derivative of f(x)=3x^2-ln(x) ?
The first derivative of f(x)=3x^2-ln(x) is 6x-1/x