What is (\partial)/(\partial x)(y^4-6xy) ?

The answer to (\partial)/(\partial x)(y^4-6xy) is -6y

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(\partial)/(\partial x)(y^4-6xy)

\frac{\partial}{\partial x} (y^{4} - 6 x y)

- 6 y

Solution steps

\frac{\partial}{\partial x} (y^{4} - 6 x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{4}) - \frac{\partial}{\partial x} (6 x y)

\frac{\partial}{\partial x} (y^{4}) = 0

\frac{\partial}{\partial x} (6 x y) = 6 y

= 0 - 6 y

Simplify

= - 6 y

y^{^{'}} + 4 y = e^{3 x}

x \to 0 lim (\frac{1}{1})

\int (x^{2} + 6) sin (2 x) d x

ln (e + x)

\int_{0}^{0.5} x (4 - 8 x) d x

What is (\partial)/(\partial x)(y^4-6xy) ?
The answer to (\partial)/(\partial x)(y^4-6xy) is -6y