What is maclaurin 1/(1+2x^3) ?

The answer to maclaurin 1/(1+2x^3) is 1-2x^3+4x^6-8x^9+\ldots

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maclaurin 1/(1+2x^3)

maclaurin

\frac{1}{1 + 2 x ^{3}}

1 - 2 x^{3} + 4 x^{6} - 8 x^{9} + \dots

Solution steps

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( \frac{1}{1 + 2 x ^{3}} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{1}{1 + 2 x ^{3}} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{1}{1 + 2 x ^{3}} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{0}{1 !} x + \frac{0}{2 !} x^{2} + \frac{- 12}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{2880}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{- 2903040}{9 !} x^{9} + \frac{0}{10 !} x^{10} + \dots

Refine

= 1 - 2 x^{3} + 4 x^{6} - 8 x^{9} + \dots

\int sec^{14} (x) tan (x) d x

\frac{d}{d x} (\frac{12}{x ^{5}})

\int sin (t) d t

\frac{d y}{d t} = y (8 - y)

\int \frac{1}{( x + 2 )} d x

What is maclaurin 1/(1+2x^3) ?
The answer to maclaurin 1/(1+2x^3) is 1-2x^3+4x^6-8x^9+\ldots