What is the limit as x approaches 0 of x^3sin(1/x) ?

The limit as x approaches 0 of x^3sin(1/x) is 0

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limit as x approaches 0 of x^3sin(1/x)

x \to 0 lim (x^{3} sin (\frac{1}{x}))

0

Solution steps

x \to 0 lim (x^{3} sin (\frac{1}{x}))

Apply the Squeeze Theorem:

0

= 0

f (x) = 2 sec (x)

f (x) = π^{9}

\frac{18}{( x - 6 ) ^{2}}

y^{^{''}} + 6 y^{^{'}} + 9 y = t + e^{3 t}

\int \frac{x ^{2} + 5 x + 12}{x} d x

What is the limit as x approaches 0 of x^3sin(1/x) ?
The limit as x approaches 0 of x^3sin(1/x) is 0