What is the solution for y^'=cos(y-x+3) ?

The solution for y^'=cos(y-x+3) is y=2arccot(x+c_{1})+2pin+x-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=cos(y-x+3)

y^{^{'}} = cos (y - x + 3)

y = 2 arccot (x + c_{1}) + 2 πn + x - 3

Solution steps

y^{'} (x) = cos (y - x + 3)

Solve using substitution:

y = 2 arccot (x + c_{1}) + 2 πn + x - 3

y = 2 arccot (x + c_{1}) + 2 πn + x - 3

\int 7 tan (7 x) d x

\int 3 tan (x) d x

\frac{d}{d t} (\frac{t}{t ^{2} + 16})

- x^{3} + x^{2} + 16 x, 4 x

\int \frac{2 x - 3}{x ^{3} + x} d x

What is the solution for y^'=cos(y-x+3) ?
The solution for y^'=cos(y-x+3) is y=2arccot(x+c_{1})+2pin+x-3