What is the derivative of (ln(x+1)^2) ?

The derivative of (ln(x+1)^2) is (2ln(x+1))/(x+1)

What is the first derivative of (ln(x+1)^2) ?

The first derivative of (ln(x+1)^2) is (2ln(x+1))/(x+1)

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\frac{d}{d x} ((ln (x + 1))^{2})

\frac{2 ln ( x + 1 )}{x + 1}

Solution steps

\frac{d}{d x} ((ln (x + 1))^{2})

Apply the chain rule:

2 ln (x + 1) \frac{d}{d x} (ln (x + 1))

= 2 ln (x + 1) \frac{d}{d x} (ln (x + 1))

\frac{d}{d x} (ln (x + 1)) = \frac{1}{x + 1}

= 2 ln (x + 1) \frac{1}{x + 1}

Simplify

2 ln (x + 1) \frac{1}{x + 1} : \frac{2 ln ( x + 1 )}{x + 1}

= \frac{2 ln ( x + 1 )}{x + 1}

y = 9 x, y = x^{2} - 10, y = 0

y^{^{'}} + 3 x^{2} y = 0

\int_{1}^{3} \frac{6}{x ^{2}} d x

\int 121 - x^{2} d x

What is the derivative of (ln(x+1)^2) ?
The derivative of (ln(x+1)^2) is (2ln(x+1))/(x+1)
What is the first derivative of (ln(x+1)^2) ?
The first derivative of (ln(x+1)^2) is (2ln(x+1))/(x+1)