What is (\partial)/(\partial w)(2x^2w^3(z-1)) ?

The answer to (\partial)/(\partial w)(2x^2w^3(z-1)) is 6x^2w^2(z-1)

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(\partial)/(\partial w)(2x^2w^3(z-1))

\frac{\partial}{\partial w} (2 x^{2} w^{3} (z - 1))

6 x^{2} w^{2} (z - 1)

Solution steps

\frac{\partial}{\partial w} (2 x^{2} w^{3} (z - 1))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 x^{2} (z - 1) \frac{\partial}{\partial w} (w^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 x^{2} (z - 1) \cdot 3 w^{3 - 1}

Simplify

= 6 x^{2} w^{2} (z - 1)

\frac{d}{d x} (\frac{4 - sec ( x )}{tan ( x )})

\frac{\partial}{\partial x} (12 x y)

\frac{d}{d x} (\frac{x + 4}{x - 4})

\int - cos^{2} (x) sin (x) d x

\int (5 cos (x) + 4 sin (x)) d x

What is (\partial)/(\partial w)(2x^2w^3(z-1)) ?
The answer to (\partial)/(\partial w)(2x^2w^3(z-1)) is 6x^2w^2(z-1)