What is the (sin(x)+xcos(x))^' ?

The (sin(x)+xcos(x))^' is 2cos(x)-xsin(x)

What is the first (sin(x)+xcos(x))^' ?

The first (sin(x)+xcos(x))^' is 2cos(x)-xsin(x)

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(sin (x) + x cos (x))^{^{'}}

2 cos (x) - x sin (x)

Solution steps

(sin (x) + x cos (x))^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (sin (x))^{^{'}} + (x cos (x))^{^{'}}

(sin (x))^{'} = cos (x)

(x cos (x))^{'} = cos (x) - x sin (x)

= cos (x) + cos (x) - x sin (x)

Simplify

= 2 cos (x) - x sin (x)

\int \frac{2 e ^{2 x}}{e ^{10} - 1} d x

\int \frac{1}{( 121 + x ^{2} ) ^{2}} d x

\int \frac{( x ^{2} + 2 x - 2 )}{x ^{3} - 4 x} d x

\int - 6 e^{- 6 x} d x

\int \frac{3}{1000 + 2 t} d t

What is the (sin(x)+xcos(x))^' ?
The (sin(x)+xcos(x))^' is 2cos(x)-xsin(x)
What is the first (sin(x)+xcos(x))^' ?
The first (sin(x)+xcos(x))^' is 2cos(x)-xsin(x)