What is the derivative of (3cos(2x+sin(3x))^2) ?

The derivative of (3cos(2x+sin(3x))^2) is 2(3cos(2x)+sin(3x))(-6sin(2x)+cos(3x)*3)

What is the first derivative of (3cos(2x+sin(3x))^2) ?

The first derivative of (3cos(2x+sin(3x))^2) is 2(3cos(2x)+sin(3x))(-6sin(2x)+cos(3x)*3)

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\frac{d}{d x} ((3 cos (2 x) + sin (3 x))^{2})

2 (3 cos (2 x) + sin (3 x)) (- 6 sin (2 x) + cos (3 x) \cdot 3)

Solution steps

\frac{d}{d x} ((3 cos (2 x) + sin (3 x))^{2})

Apply the chain rule:

2 (3 cos (2 x) + sin (3 x)) \frac{d}{d x} (3 cos (2 x) + sin (3 x))

= 2 (3 cos (2 x) + sin (3 x)) \frac{d}{d x} (3 cos (2 x) + sin (3 x))

\frac{d}{d x} (3 cos (2 x) + sin (3 x)) = - 6 sin (2 x) + cos (3 x) \cdot 3

= 2 (3 cos (2 x) + sin (3 x)) (- 6 sin (2 x) + cos (3 x) \cdot 3)

\int (x^{- 1}) d x

\int 4 t e^{4 t} d t

\int 6 x^{2} + 4 d x

e^{\frac{t}{9}} sin (\frac{t}{9})

\int 8 (tan (8 x)) d x

What is the derivative of (3cos(2x+sin(3x))^2) ?
The derivative of (3cos(2x+sin(3x))^2) is 2(3cos(2x)+sin(3x))(-6sin(2x)+cos(3x)*3)
What is the first derivative of (3cos(2x+sin(3x))^2) ?
The first derivative of (3cos(2x+sin(3x))^2) is 2(3cos(2x)+sin(3x))(-6sin(2x)+cos(3x)*3)