What is (\partial)/(\partial x)(6yx^5-20y^2x^4) ?

The answer to (\partial)/(\partial x)(6yx^5-20y^2x^4) is 30yx^4-80y^2x^3

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(\partial)/(\partial x)(6yx^5-20y^2x^4)

\frac{\partial}{\partial x} (6 y x^{5} - 20 y^{2} x^{4})

30 y x^{4} - 80 y^{2} x^{3}

Solution steps

\frac{\partial}{\partial x} (6 y x^{5} - 20 y^{2} x^{4})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (6 y x^{5}) - \frac{\partial}{\partial x} (20 y^{2} x^{4})

\frac{\partial}{\partial x} (6 y x^{5}) = 30 y x^{4}

\frac{\partial}{\partial x} (20 y^{2} x^{4}) = 80 y^{2} x^{3}

= 30 y x^{4} - 80 y^{2} x^{3}

y = x, y = 2 x

\frac{\partial}{\partial x} (cos (x) sin (y))

\frac{d}{d x} ((3 x)^{\frac{1}{3}})

x^{2}, 2 x - x^{2}

\frac{1}{s - a}

What is (\partial)/(\partial x)(6yx^5-20y^2x^4) ?
The answer to (\partial)/(\partial x)(6yx^5-20y^2x^4) is 30yx^4-80y^2x^3