What is the derivative of 2/(3x^4) ?

The derivative of 2/(3x^4) is -8/(3x^5)

What is the first derivative of 2/(3x^4) ?

The first derivative of 2/(3x^4) is -8/(3x^5)

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derivative of

\frac{2}{3 x ^{4}}

- \frac{8}{3 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{2}{3 x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{2}{3} \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{2}{3} \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{2}{3} (- 4 x^{- 4 - 1})

Simplify

\frac{2}{3} (- 4 x^{- 4 - 1}) : - \frac{8}{3 x ^{5}}

= - \frac{8}{3 x ^{5}}

n = 1 \sum \infty \frac{n}{5 + n ^{2}}

2 x - x^{2}, - 2 x

\int \frac{1 + 16 x}{25 - x ^{2}} d x

\frac{d}{d x} (\frac{2 x}{3 y})

x \to 7 lim ((x^{2} - 49) (\frac{( x - 7 )}{∣ x - 7 ∣}))

What is the derivative of 2/(3x^4) ?
The derivative of 2/(3x^4) is -8/(3x^5)
What is the first derivative of 2/(3x^4) ?
The first derivative of 2/(3x^4) is -8/(3x^5)