What is the derivative of 6x+sqrt(x) ?

The derivative of 6x+sqrt(x) is 6+1/(2sqrt(x))

What is the first derivative of 6x+sqrt(x) ?

The first derivative of 6x+sqrt(x) is 6+1/(2sqrt(x))

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\frac{d}{d x} (6 x + x)

6 + \frac{1}{2 x}

Solution steps

\frac{d}{d x} (6 x + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) + \frac{d}{d x} (x)

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (x) = \frac{1}{2 x}

= 6 + \frac{1}{2 x}

\int \frac{2}{x 9 - x ^{2}} d x

x \to 0 - lim (\frac{1}{0})

f (x) = \frac{( 10 x )}{x ^{2} - 6}, at x = 4

\int (2 x + 3) sin (3 x) d x

\frac{( - 1 ) ^{n} x ^{n}}{n !}

What is the derivative of 6x+sqrt(x) ?
The derivative of 6x+sqrt(x) is 6+1/(2sqrt(x))
What is the first derivative of 6x+sqrt(x) ?
The first derivative of 6x+sqrt(x) is 6+1/(2sqrt(x))