What is the derivative of 1/((x-4^2)) ?

The derivative of 1/((x-4^2)) is -2/((x-4)^3)

What is the first derivative of 1/((x-4^2)) ?

The first derivative of 1/((x-4^2)) is -2/((x-4)^3)

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\frac{d}{d x} (\frac{1}{( x - 4 ) ^{2}})

- \frac{2}{( x - 4 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( x - 4 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 4)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 4 ) ^{3}} \frac{d}{d x} (x - 4)

= - \frac{2}{( x - 4 ) ^{3}} \frac{d}{d x} (x - 4)

\frac{d}{d x} (x - 4) = 1

= - \frac{2}{( x - 4 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( x - 4 ) ^{3}}

y = \frac{d y}{d x}

\int \frac{1}{x ^{2} ( x - 1 )} d x

\frac{\partial}{\partial x} ((x y + x + y) e^{x})

g (x) = \frac{( x ^{2} - 1 )}{x ^{2} + x + 1}

x \to 0 lim (2 x - p (x))

What is the derivative of 1/((x-4^2)) ?
The derivative of 1/((x-4^2)) is -2/((x-4)^3)
What is the first derivative of 1/((x-4^2)) ?
The first derivative of 1/((x-4^2)) is -2/((x-4)^3)