What is the solution for 6(dy)/(dx)+3e^{x+y}=0 ?

The solution for 6(dy)/(dx)+3e^{x+y}=0 is y=-ln((e^x-c_{1})/2)

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6(dy)/(dx)+3e^{x+y}=0

6 \frac{d y}{d x} + 3 e^{x + y} = 0

y = - ln (\frac{e ^{x} - c _{1}}{2})

Solution steps

6 \frac{d y}{d x} + 3 e^{x + y} = 0

Solve separable ODE:

y = - ln (\frac{e ^{x} - c _{1}}{2})

y = - ln (\frac{e ^{x} - c _{1}}{2})

g (x) = x, (1, 1)

\frac{\partial}{\partial x} (3 x cos (4 x y))

\frac{\partial}{\partial x} (9 x e^{8 x y})

\int x (x + 1)^{8} d x

\frac{d y}{d x} + y = x e^{5 x} y^{6}

What is the solution for 6(dy)/(dx)+3e^{x+y}=0 ?
The solution for 6(dy)/(dx)+3e^{x+y}=0 is y=-ln((e^x-c_{1})/2)