What is the integral of 1/(2sqrt(t)) ?

The integral of 1/(2sqrt(t)) is sqrt(t)+C

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integral of 1/(2sqrt(t))

\int \frac{1}{2 t} d t

t + C

Solution steps

\int \frac{1}{2 t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{t} d t

Apply the Power Rule

: 2 t^{\frac{1}{2}}

= \frac{1}{2} \cdot 2 t^{\frac{1}{2}}

Simplify

\frac{1}{2} \cdot 2 t^{\frac{1}{2}} : t

= t

Add a constant to the solution

= t + C

\frac{d}{d x} ((cos (x))^{2})

\int (4 x + 3) e^{3 x + 1} d x

\int \frac{1}{( 4 + x ) ^{2}} d x

y = - x^{2} + 12 x - 32, y = 0

x \to 4 lim (\frac{15}{x - 4})

What is the integral of 1/(2sqrt(t)) ?
The integral of 1/(2sqrt(t)) is sqrt(t)+C