What is the derivative of y=csc(x)-cot(x) ?

The derivative of y=csc(x)-cot(x) is 1/(1+cos(x))

What is the first derivative of y=csc(x)-cot(x) ?

The first derivative of y=csc(x)-cot(x) is 1/(1+cos(x))

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derivative of

y = csc (x) - cot (x)

\frac{1}{1 + cos ( x )}

Solution steps

\frac{d}{d x} (csc (x) - cot (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (csc (x)) - \frac{d}{d x} (cot (x))

\frac{d}{d x} (csc (x)) = - cot (x) csc (x)

\frac{d}{d x} (cot (x)) = - csc^{2} (x)

= - cot (x) csc (x) - (- csc^{2} (x))

Simplify

- cot (x) csc (x) - (- csc^{2} (x)) : \frac{1}{1 + cos ( x )}

= \frac{1}{1 + cos ( x )}

n = 1 \sum \infty n^{2} x^{n}

\int_{0}^{2 π} sin^{3} (x) d x

\int x^{3} + 2 d x

x \to 15 lim (x + 3)

\int \frac{4 - x}{( x + 2 ) ( x ^{2} + 2 )} d x

What is the derivative of y=csc(x)-cot(x) ?
The derivative of y=csc(x)-cot(x) is 1/(1+cos(x))
What is the first derivative of y=csc(x)-cot(x) ?
The first derivative of y=csc(x)-cot(x) is 1/(1+cos(x))