What is the tangent of y=5x^3-5x,(-1,0) ?

The tangent of y=5x^3-5x,(-1,0) is y=10x+10

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tangent of y=5x^3-5x,(-1,0)

tangent of

y = 5 x^{3} - 5 x, (- 1, 0)

y = 10 x + 10

Solution steps

Find the slope of

y = 5 x^{3} - 5 x : \frac{d y}{d x} = 15 x^{2} - 5

Compute the slope of

y = 5 x^{3} - 5 x

(- 1, 0) : m = 10

Find the line with slope m=

10

and passing through

(- 1, 0) : y = 10 x + 10

y = 10 x + 10

\frac{1000}{s + 1000}

\frac{d}{d x} (\frac{2 2}{x ^{2}})

\int arctan (8 x) d x

\frac{d}{d x} (7^{x} ln (7))

\frac{3 e ^{x}}{( 3 + e ^{x} ) ^{2}}

What is the tangent of y=5x^3-5x,(-1,0) ?
The tangent of y=5x^3-5x,(-1,0) is y=10x+10