What is the solution for (dy}{dx}=\frac{x^2+2y)/x ?

The solution for (dy}{dx}=\frac{x^2+2y)/x is y=ln(x)x^2+c_{1}x^2

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(dy}{dx}=\frac{x^2+2y)/x

\frac{d y}{d x} = \frac{x ^{2} + 2 y}{x}

y = ln (x) x^{2} + c_{1} x^{2}

Solution steps

\frac{d y}{d x} = \frac{x ^{2} + 2 y}{x}

Solve linear ODE:

y = ln (x) x^{2} + c_{1} x^{2}

y = ln (x) x^{2} + c_{1} x^{2}

\int (\frac{x + 11}{x - 9}) d x

\int_{0}^{3} f (x) d x

\int x^{3} e^{- x^{4}} d x

f (x) = cot^{t a n (x)} (x)

y = \frac{x}{1 + x ^{2}}

What is the solution for (dy}{dx}=\frac{x^2+2y)/x ?
The solution for (dy}{dx}=\frac{x^2+2y)/x is y=ln(x)x^2+c_{1}x^2