What is the derivative of (2x^3-3x+2^4) ?

The derivative of (2x^3-3x+2^4) is 4(2x^3-3x+2)^3(6x^2-3)

What is the first derivative of (2x^3-3x+2^4) ?

The first derivative of (2x^3-3x+2^4) is 4(2x^3-3x+2)^3(6x^2-3)

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\frac{d}{d x} ((2 x^{3} - 3 x + 2)^{4})

4 (2 x^{3} - 3 x + 2)^{3} (6 x^{2} - 3)

Solution steps

\frac{d}{d x} ((2 x^{3} - 3 x + 2)^{4})

Apply the chain rule:

4 (2 x^{3} - 3 x + 2)^{3} \frac{d}{d x} (2 x^{3} - 3 x + 2)

= 4 (2 x^{3} - 3 x + 2)^{3} \frac{d}{d x} (2 x^{3} - 3 x + 2)

\frac{d}{d x} (2 x^{3} - 3 x + 2) = 6 x^{2} - 3

= 4 (2 x^{3} - 3 x + 2)^{3} (6 x^{2} - 3)

x \to 2 - lim (\frac{x + 2}{x - 3})

\int \frac{x ^{2}}{x ^{3} + 2} d x

f (x) = 3 x + 4 (7.5)

y = x^{3}, (0, 1)

y^{^{'}} = \frac{2 t}{1 + 2 y}

What is the derivative of (2x^3-3x+2^4) ?
The derivative of (2x^3-3x+2^4) is 4(2x^3-3x+2)^3(6x^2-3)
What is the first derivative of (2x^3-3x+2^4) ?
The first derivative of (2x^3-3x+2^4) is 4(2x^3-3x+2)^3(6x^2-3)