What is the tangent of y=\sqrt[4]{x},(1,1) ?

The tangent of y=\sqrt[4]{x},(1,1) is y= 1/4 x+3/4

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tangent of y=\sqrt[4]{x},(1,1)

tangent of

y = \frac{1}{4} x + \frac{3}{4}

Solution steps

Find the slope of

Compute the slope of

(1, 1) : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(1, 1) : y = \frac{1}{4} x + \frac{3}{4}

y = \frac{1}{4} x + \frac{3}{4}

\frac{d}{d x} (- 2 e^{3 x} sin (2 x))

f (x) = \frac{4 x}{( x ^{3} - 6 ) ^{2}}

y^{^{''}} + 3 y^{^{'}} + y = 1, y (0) = 1, y^{^{'}} (0) = 0

x \to 0 lim (c e^{x} + 1)

\int 1 - \frac{1}{x} d x

What is the tangent of y=\sqrt[4]{x},(1,1) ?
The tangent of y=\sqrt[4]{x},(1,1) is y= 1/4 x+3/4