What is the integral of 2050-18x-4x^2 ?

The integral of 2050-18x-4x^2 is 2050x-9x^2-(4x^3)/3+C

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integral of 2050-18x-4x^2

\int 2050 - 18 x - 4 x^{2} d x

2050 x - 9 x^{2} - \frac{4 x ^{3}}{3} + C

Solution steps

\int 2050 - 18 x - 4 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2050 d x - \int 18 x d x - \int 4 x^{2} d x

\int 2050 d x = 2050 x

\int 18 x d x = 9 x^{2}

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

= 2050 x - 9 x^{2} - \frac{4 x ^{3}}{3}

Add a constant to the solution

= 2050 x - 9 x^{2} - \frac{4 x ^{3}}{3} + C

- y^{^{'}} + \frac{4 y}{x} = x^{3} y^{2}

f (x) = \frac{3}{x}, at x = - 4

\int \frac{5 + x + x}{x} d x

\int \frac{( 3 + x + x ^{2} )}{x} d x

x \to 2 lim (x^{2} - 2 x + 4)

What is the integral of 2050-18x-4x^2 ?
The integral of 2050-18x-4x^2 is 2050x-9x^2-(4x^3)/3+C