What is the solution for x(dy)/(dx)+2y=x^{-3} ?

The solution for x(dy)/(dx)+2y=x^{-3} is y=-1/(x^3)+(c_{1})/(x^2)

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x(dy)/(dx)+2y=x^{-3}

x \frac{d y}{d x} + 2 y = x^{- 3}

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

Solution steps

x \frac{d y}{d x} + 2 y = x^{- 3}

Solve linear ODE:

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

y = - \frac{1}{x ^{3}} + \frac{c _{1}}{x ^{2}}

y = e^{2 x} + e^{- 2 x}

\frac{d y}{d x} = x + y, y (0) = 0

f (x) = 3 e^{- 2 x} ln (x)

\frac{d}{d x} (arcsin (5 x^{3}))

\frac{d}{d x} (ln ∣ csc (3 x) ∣)

What is the solution for x(dy)/(dx)+2y=x^{-3} ?
The solution for x(dy)/(dx)+2y=x^{-3} is y=-1/(x^3)+(c_{1})/(x^2)