What is (\partial)/(\partial x)(3x^2-2y^3) ?

The answer to (\partial)/(\partial x)(3x^2-2y^3) is 6x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(3x^2-2y^3)

\frac{\partial}{\partial x} (3 x^{2} - 2 y^{3})

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} - 2 y^{3})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) - \frac{\partial}{\partial x} (2 y^{3})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 y^{3}) = 0

= 6 x - 0

Simplify

= 6 x

\frac{d ^{2}}{d x ^{2}} (cos (x^{2}))

\frac{d}{d t} (1 + \frac{y}{t})

\int (x + 3) 5 - x d x

f (x) = \frac{1}{x ^{\frac{1}{2}}}

\int \frac{162}{x ^{2} 81 - x ^{2}} d x

What is (\partial)/(\partial x)(3x^2-2y^3) ?
The answer to (\partial)/(\partial x)(3x^2-2y^3) is 6x