What is the solution for (x+y)dx+x^2dy=0 ?

The solution for (x+y)dx+x^2dy=0 is y=\Ei(-1/x)e^{1/x}+c_{1}e^{1/x}

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(x+y)dx+x^2dy=0

(x + y) d x + x^{2} d y = 0

y = Ei (- \frac{1}{x}) e^{\frac{1}{x}} + c_{1} e^{\frac{1}{x}}

Solution steps

(x + y) d x + x^{2} d y = 0

Solve linear ODE:

y = Ei (- \frac{1}{x}) e^{\frac{1}{x}} + c_{1} e^{\frac{1}{x}}

y = Ei (- \frac{1}{x}) e^{\frac{1}{x}} + c_{1} e^{\frac{1}{x}}

\frac{\partial}{\partial x} (1 (x - y) \cdot e^{1 y + 4 x^{2}})

\frac{d ^{3}}{d x ^{3}} (6 x + 3)

\int_{0}^{s i n (x)} 8 t d t

\int - x - 3 d x

h (x) = (x^{2} - 3)^{3}

What is the solution for (x+y)dx+x^2dy=0 ?
The solution for (x+y)dx+x^2dy=0 is y=\Ei(-1/x)e^{1/x}+c_{1}e^{1/x}