What is (\partial)/(\partial y)(3x^2-5y) ?

The answer to (\partial)/(\partial y)(3x^2-5y) is -5

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(\partial)/(\partial y)(3x^2-5y)

\frac{\partial}{\partial y} (3 x^{2} - 5 y)

- 5

Solution steps

\frac{\partial}{\partial y} (3 x^{2} - 5 y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) - \frac{\partial}{\partial y} (5 y)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (5 y) = 5

= 0 - 5

Simplify

= - 5

y^{^{'}} = \frac{x y ^{2} - 0.5 sin ( 2 x )}{y ( 1 - x ^{2} )}

y^{^{'''}} + 2 y^{^{''}} + y^{^{'}} = 0

x \to a lim (9)

\frac{2 s + 1}{s ^{2} + 2 s + 5}

y = x^{2} + x + 3, at x = 3.99

What is (\partial)/(\partial y)(3x^2-5y) ?
The answer to (\partial)/(\partial y)(3x^2-5y) is -5