What is inverse oflaplace (0.1)/(s+0.1) ?

The answer to inverse oflaplace (0.1)/(s+0.1) is 0.1e^{-0.1t}

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inverse oflaplace (0.1)/(s+0.1)

inverse laplace

\frac{0.1}{s + 0.1}

0.1 e^{- 0.1 t}

Solution steps

L^{- 1} {\frac{0.1}{s + 0.1}}

= L^{- 1} {0.1 \cdot \frac{1}{s + 0.1}}

Use the constant multiplication property of Inverse Laplace Transform:

For function

f (t)

and constant

a : L^{- 1} {a \cdot f (t)} = a \cdot L^{- 1} {f (t)}

= 0.1 L^{- 1} {\frac{1}{s + 0.1}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{1}{s - a}} = e^{a t}

L^{- 1} {\frac{1}{s + 0.1}} = e^{- 0.1 t}

= 0.1 e^{- 0.1 t}

\frac{d}{d x} (x z + x y + y z)

\int_{2}^{3} \frac{x ^{4} + 1}{x ^{5} + 5 x} d x

(ln (\frac{1 + x}{1 - x}))^{^{'}}

\int \frac{( x ^{2} - 1 )}{x ^{2} + 1} d x

\int 2 x (x^{2} + 1)^{3} d x

What is inverse oflaplace (0.1)/(s+0.1) ?
The answer to inverse oflaplace (0.1)/(s+0.1) is 0.1e^{-0.1t}